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Therefore, for the core experiment, we have utilised within 0.020.1 gL 1 [25]
This is thought to occur because NADH is an inhibitor of these enzymes, so lowering it releases the inhibition.[4] Transferring electrons in NAD(P) redox reactions does not have a large effect on the total pool of NAD(P), since, rather than being broken down (catabolized), the NAD(P) molecule is interconverted between oxidized and reduced forms
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Neuropharmacology 24 , 391399 (1985)